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x^2+9.6x=81
We move all terms to the left:
x^2+9.6x-(81)=0
a = 1; b = 9.6; c = -81;
Δ = b2-4ac
Δ = 9.62-4·1·(-81)
Δ = 416.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.6)-\sqrt{416.16}}{2*1}=\frac{-9.6-\sqrt{416.16}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.6)+\sqrt{416.16}}{2*1}=\frac{-9.6+\sqrt{416.16}}{2} $
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